Algebra

br JavaScript is required for your ancestry . ensure JavaScript is enabled in your browser preferencesSeminar on additive Equations , Inequalities and GraphingTo unclutter seminar credit for this unit , tax return one of the following options belowOption 1 : Participate in a synchronous seminar (Note : Students atomic name 18 encouraged to envision seminar but the educatee may complete Option 2 instead of aid seminarThe seminar s is Linear Equations , Inequalities and Graphing complete the Unit 3 reading sooner attend the seminar session in to be familiar with the unavoidable linguistic process and concepts Concepts and example problems will be discussed , supplementing the material cover by the textbookOption 2 : Complete the inviolate problem amaze below1 . reclaim the mid gratuity of the crimp segment PQ for(2 , -2 , Q (3 , 4Solution : The mid turn on can be reckon asx (2 3 /2 5 /2y (-2 4 /2 2 /2 1Hence , the midpoint is (5 /2 , 12 .

If M (6 , 1 ) is the midpoint of segment PQ and the coordinates of Q ar (2 , -2 , find the coordinates ofp Solution : let the coordinates of pointbe (x , yThen (x 2 /2 6 and (y (-2 /2 1Therefore , x 2 12 and y - 2 2Therefore , x 10 and y 4Hence the pointis (10 , 43 . Verify that (-1 , 3 ) is a solution to y (-1 /2 )x (5 /2Solution : Substituting x -1 and y 3 in the given equation yieldsRHS (-1 /2 )x (5 /2 (-1 /2 (-1 (5 /2 (1 /2 (5 /2 3 y LHSHence (-1 , 3 ) is a solution of the given equation4 . vague up the distinction and salve the solution curing in detachment notation5 . Solve the inequality and write the solution gravel in interval notation SolutionGiven (3 /5 )x (2 /3 (x - 5 x FGHGYUHMAjtE /3 )x - (10 /3 xTherefore (3 /5 )x (2 /3 )x -x 10 /3Therefore (9 10 - 15 /15 )x 10 /3Therefore (4 /15 )x 10 /3Therefore , x (10 15 (4 3Hence , x 25 /2Hence , the solution set is (- , 25 /2...If you want to birth a full essay, society it on our website: Ordercustompaper.com

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